![]() ![]() Initializes a new instance of the Semaphore class, specifying the initial number of entries and the maximum number of concurrent entries, and optionally specifying the name of a system semaphore object. Initializes a new instance of the Semaphore class, specifying the initial number of entries and the maximum number of concurrent entries. Each Semaphore object is a separate local semaphore. It can be used by any thread in your process that has a reference to the local Semaphore object. You can create multiple Semaphore objects that represent the same named system semaphore, and you can use the OpenExisting method to open an existing named system semaphore.Ī local semaphore exists only within your process. Named system semaphores are visible throughout the operating system, and can be used to synchronize the activities of processes. If you create a Semaphore object using a constructor that accepts a name, it is associated with an operating-system semaphore of that name. Semaphores are of two types: local semaphores and named system semaphores. The count on the semaphore is full, and when thread A eventually calls Release, a SemaphoreFullException is thrown. If a programming error in thread B causes it to call Release twice, both calls succeed. For example, suppose a semaphore has a maximum count of two, and that thread A and thread B both enter the semaphore. It is the programmer's responsibility to ensure that threads do not release the semaphore too many times. The Semaphore class does not enforce thread identity on calls to WaitOne or Release. To release some or all of these entries, the thread can call the parameterless Release() method overload multiple times, or it can call the Release(Int32) method overload that specifies the number of entries to be released. There is no guaranteed order, such as FIFO or LIFO, in which blocked threads enter the semaphore.Ī thread can enter the semaphore multiple times, by calling the WaitOne method repeatedly. When all threads have released the semaphore, the count is at the maximum value specified when the semaphore was created. When the count is zero, subsequent requests block until other threads release the semaphore. The count on a semaphore is decremented each time a thread enters the semaphore, and incremented when a thread releases the semaphore. Threads enter the semaphore by calling the WaitOne method, which is inherited from the WaitHandle class, and release the semaphore by calling the Release method. ![]() Use the Semaphore class to control access to a pool of resources. Each worker thread begins by requesting theĬonsole::WriteLine( L"Thread ", _ allows the waiting threads to enter the semaphore,Ĭonsole::WriteLine( L"Main thread calls Release(3)." ) Ĭonsole::WriteLine( L"Main thread exits." ) semaphore count back to its maximum value, and The main thread starts out holding the entire threads to start and to block on the semaphore. Wait for half a second, to allow all the Create and start five numbered threads. so that the entire semaphore count is initially Create a semaphore that can satisfy up to three A padding interval to make the output more orderly. A semaphore that simulates a limited resource pool. The simulated work interval is increased slightly for each thread, to make the output easier to read. Each time the semaphore is released, the previous semaphore count is displayed. Each thread uses the Thread.Sleep method to wait for one second, to simulate work, and then calls the Release() method overload to release the semaphore. The main thread uses the Release(Int32) method overload to increase the semaphore count to its maximum, allowing three threads to enter the semaphore. The example starts five threads, which block waiting for the semaphore. The following code example creates a semaphore with a maximum count of three and an initial count of zero. ![]()
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